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Borel right process
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Borel right process : ウィキペディア英語版
Borel right process

In the mathematical theory of probability, a Borel right process, named after Émile Borel, is a particular kind of continuous-time random process.
Let E be a locally compact, separable, metric space.
We denote by \mathcal E the Borel subsets of E.
Let \Omega be the space of right continuous maps from , B \in \mathcal E^
*\right\},

and then, let
:
\mathcal F_\infty = \sigma\left\(B) : s\in and the mapping given by t \rightarrow X_t is right continuous, we see that
for any uniformly continuous function f, we have the mapping given by t \rightarrow P_tf(x) is right continuous.
Therefore, together with the monotone class theorem, for any universally measurable function f, the mapping given by (t,x) \rightarrow P_tf(x), is jointly measurable, that is, \mathcal B([0,\infty))\otimes \mathcal E^
* measurable, and subsequently, the mapping is also \left(\mathcal B([0,\infty))\otimes \mathcal E^
*\right)^-measurable for all finite measures \lambda on \mathcal B([0,\infty)) and \mu on \mathcal E^
*.
Here,
\left(\mathcal B([0,\infty))\otimes \mathcal E^
*\right)^ is the completion of
\mathcal B([0,\infty))\otimes \mathcal E^
* with respect
to the product measure \lambda \otimes \mu.
Thus, for any bounded universally measurable function f on E,
the mapping t\rightarrow P_tf(x) is Lebeague measurable, and hence,
for each \alpha \in [0,\infty) , one can define
:
U^\alpha f(x) = \int_0^\infty e^P_tf(x) dt.

There is enough joint measurability to check that \ is a Markov resolvent on (E,\mathcal E^
*),
which uniquely associated with the Markovian semigroup \.
Consequently, one may apply Fubini's theorem to see that
:
U^\alpha f(x) = \mathbf E^x\left[ \int_0^\infty e^ f(X_t) dt \right].

The followings are the defining properties of Borel right processes:
* Hypothesis Droite 1:
:For each probability measure \mu on (E, \mathcal E), there exists a probability measure \mathbf P^\mu on (\Omega, \mathcal F^
*) such that (X_t, \mathcal F_t^
*, P^\mu) is a Markov process with initial measure \mu and transition semigroup \.
* Hypothesis Droite 2:
:Let f be \alpha-excessive for the resolvent on (E, \mathcal E^
*). Then, for each probability measure \mu on (E,\mathcal E), a mapping given by t \rightarrow f(X_t) is P^\mu almost surely right continuous on [0,\infty).


抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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